SOLUTION: what do the graphs for y=1/12(x)^2 and x+-1/4(y)^2 look like

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Question 610321: what do the graphs for y=1/12(x)^2 and x+-1/4(y)^2 look like

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
what do the graphs for y=1/12(x)^2 and x = -1/4(y)^2 look like ||Assume the + was an = sign
the vertex form of a parabola opening up or down, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex.The standard form is %28x+-h%29%5E2+=+4p%28y+-k%29, where the focus is (h,k + p)
y=%281%2F12%29%28x%29%5E2+ opens Upward as a = 1/12 > 0 Green
the vertex form of a parabola opening right or left, x=a%28y-k%29%5E2+%2Bh where(h,k) is the vertex.The standard form is %28y+-k%29%5E2+=+4p%28x+-h%29, where the focus is (h +p,k )
x+=+%28-1%2F4%29%28y%29%5E2 opens to the LEFT as a = -1/4 < 0