SOLUTION: What is the minimum value of the function y = 3^2 + 2x – 8?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: What is the minimum value of the function y = 3^2 + 2x – 8?       Log On


   

Question 609197: What is the minimum value of the function y = 3^2 + 2x – 8?
Found 2 solutions by lwsshak3, ewatrrr:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
What is the minimum value of the function y = 3^2 + 2x – 8
**
I don't think you wrote the function correctly which is a straight line with slope=2 and y-intercept=1. Function as written has no maximum or minimum.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

Assume You meant: y = 3x^2 + 2x – 8

Using the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

y = 3x^2 + 2x – 8

y = 3(x + 1/3)^2 - 1/3- 8    ||vertex(-1/3, -25/3 )min, a=3>0, parbola opens