SOLUTION: -x^2 + y^2 - 6x -10y +17=0 a.find the vertices b.find the length of the focal radius c.find the slopes of the asymptotes d.find the length of the conjugate axis. I dont know

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: -x^2 + y^2 - 6x -10y +17=0 a.find the vertices b.find the length of the focal radius c.find the slopes of the asymptotes d.find the length of the conjugate axis. I dont know       Log On


   



Question 608650: -x^2 + y^2 - 6x -10y +17=0
a.find the vertices
b.find the length of the focal radius
c.find the slopes of the asymptotes
d.find the length of the conjugate axis.
I dont know if it is a circle or a hyperbola.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi
-x^2 + y^2 - 6x -10y +17=0
x^2 - y^2 + 6x +10y -17=0 ||multiplying thru by -1
(x+3)^2 -9 -(y-5)^2+25-17=0
%28x%2B3%29%5E2+-%28y-5%29%5E2=1+ |Note: C(-3,5) a=1 and b = 1
Note:
Standard Form of an Equation of an Hyperbola opening right and left is:
%28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 where Pt(h,k) is a center with vertices 'a' units right and left of center.
a.find the vertices: with Center(-3,5)and a=1..V(-4,5) and V(-2,5)
b.find the length of the focal radius sqrt%28a%5E2%2Bb%5E2%29=+highlight%28sqrt%282%29%29
c.find the slopes of the asymptotes m = ±b/a = ± +1
d.find the length of the conjugate axis: 2b is the conjugate axis length = 2

See below descriptions of various conics
_______________________________________________________________________
Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2
where Pt(h,k) is the center and r is the radius
Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+ where Pt(h,k) is the center. (a positioned to correspond with major axis)
a and b are the respective vertices distances from center and ±sqrt%28a%5E2-b%5E2%29are the foci distances from center: a > b
Standard Form of an Equation of an Hyperbola opening right and left is:
%28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 where Pt(h,k) is a center with vertices 'a' units right and left of center.
Standard Form of an Equation of an Hyperbola opening up and down is:
%28y-k%29%5E2%2Fb%5E2+-+%28x-h%29%5E2%2Fa%5E2+=+1 where Pt(h,k) is a center with vertices 'b' units up and down from center.
the vertex form of a parabola opening up or down, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex.
The standard form is %28x+-h%29%5E2+=+4p%28y+-k%29, where the focus is (h,k + p)
the vertex form of a parabola opening right or left, x=a%28y-k%29%5E2+%2Bh where(h,k) is the vertex.
The standard form is %28y+-k%29%5E2+=+4p%28x+-h%29, where the focus is (h +p,k )