Question 606785: PLEASE HELP!!! IM SO CONFUSED!!! Thank you!
Write the standard equation of this conic section:
y^2-x^2+2y-14x-57 Found 3 solutions by lwsshak3, ewatrrr, josmiceli:Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Write the standard equation of this conic section:
y^2-x^2+2y-14x-57=0
complete the square
(y^2+2y+1)-(x^2+14x+49)=57+1-49
(y+1)^2-(x+7)^2=9
(y+1)^2/9-(x+7)^2/9=1
This is an equation of a hyperbola with vertical transverse axis.
Its standard form of equation: (y-k)^2/a^2-(x-h)^2=1, (h,k)=(x,y) coordinates of center.
For given equation:
center: (-7,-1)
a^2=9
b^2=9
Hi,
Write the standard equation of this conic section:
y^2-x^2+2y-14x-57
(y^2+2y+1)-1 -(x^2+14x+49)+ 49 - 57 = 0
(y+1)^2 - (x+7)^2 = 9
Standard Form:
Standard Form of an Equation of an Hyperbola opening up and down is: where Pt(h,k) is a center with vertices 'b' units up and down from center.
You can put this solution on YOUR website! Actually, you didn't give me an equation, so
I can't give you an equation. You need an "="
sign somewhere, so I'll assume you have
------------
Add to both sides
Rearrange the terms on the left
Complete the square for the y terms and the x terms
Divide both sides by
This is a hyperbola with center at (-7,-1)
(