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Question 603328: How do I find an equation of the parabola with focus(0,-pi) and directrix y = pi
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! How do I find an equation of the parabola with focus(0,-pi) and directrix y = pi
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This is a parabola that opens downwards.
Its standard form of equation: (x-h)^2=-4p(y-k)
Axis of symmetry: x=0 or y-axis
Focus and vertex always on axis of symmetry
y-coordinate of vertex: halfway between focus and directrix on axis of symmetry
Vertex: (0,0)
P=π (distance from focus or directrix to vertex on axis of symmetry)
4p=4π
Equation: x^2=-4πy
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