SOLUTION: im doing conic sections my homework asks me to graph {{{(x-2)^2 over 4 +(y-3)^2
over 16 =1}}} over means divided by if you could help me that would be very appricated.
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-> SOLUTION: im doing conic sections my homework asks me to graph {{{(x-2)^2 over 4 +(y-3)^2
over 16 =1}}} over means divided by if you could help me that would be very appricated.
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Question 599384: im doing conic sections my homework asks me to graph over means divided by if you could help me that would be very appricated. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! (x-2)^2 over 4 +(y-3)^2 over 16=1
(x-2)^2/4+(y-3)^2/16=1
This is an equation of an ellipse with vertical major axis.
Its standard form: (x-h)^2/b^2+(y-k)^2/a^2=1, a>b, (h,k)=(x,y) coordinates of center
..
For given equation:
Center: (2,3)
a^2=16
a=√16=4
length of vertical major axis=2a=8
b^2=4
b=2
length of minor axis=2b=4
y=±(16-4(x-2)^2)^.5+3
see graph below
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