SOLUTION: write in equation in vertex form and identify the conic section and graph it. x^2+y^2+14y=-13

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: write in equation in vertex form and identify the conic section and graph it. x^2+y^2+14y=-13      Log On


   

Question 597194: write in equation in vertex form and identify the conic section and graph it.
x^2+y^2+14y=-13
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
write in equation in vertex form and identify the conic section and graph it.
x^2+y^2+14y=-13
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x^2 + (y^2+14y+49) = -13+49
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(x-0)^2 + (y+7)^2 = 36
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Draw a circle with center at (0,-7) and radius = sqrt(36) = 6
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cheers,
Stan H.
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