You can put this solution on YOUR website! Hello,
This x^2-4x-2y=0is solved by:
Adding 2y to both sides:
x^2-4x=2y
Now divide by 2:
(x^2)/2-2x=y
factor this:
1/2(x)(x-4)
x=0
x=4
RJ
www.math-unlock.com
You don't. That is a whole set of quadratic equations. The set has infinite elements; one for each possible real value of . Without another relationship defined, you cannot determine which element of the set you are dealing with.
You can apply the quadratic formula to get an expression for the solution:
Where
, , and
You will probably want to specify an interval for such that the roots of the equation will have real values.
John
My calculator said it, I believe it, that settles it
