Question 593440: write an equation for the parabola with the focus (4,0) and vertex (2,0)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! write an equation for the parabola with the focus (4,0) and vertex (2,0)
This is a parabola that opens rightwards with equation of the standard form: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex.
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For given parabola:
axis of symmetry: x-axis or y=0
p=2 (distance from focus to vertex on axis of symmetry)
4p=8
Equation:
y^2=8(x-2)
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