SOLUTION: For the graph choose the appropriate domain and range.
16x^2 + 25y^2 =400
Graph:
http://s966.photobucket.com/albums/ae144/jsic12345/?action=view¤t=circle.gif
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Quadratic-relations-and-conic-sections
-> SOLUTION: For the graph choose the appropriate domain and range.
16x^2 + 25y^2 =400
Graph:
http://s966.photobucket.com/albums/ae144/jsic12345/?action=view¤t=circle.gif
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Question 587760: For the graph choose the appropriate domain and range.
16x^2 + 25y^2 =400
Graph:
http://s966.photobucket.com/albums/ae144/jsic12345/?action=view¤t=circle.gif Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! For the graph choose the appropriate domain and range.
16x^2 + 25y^2 =400
divide by 400
x^2/25+y^2/16=1
This is an equation of an ellipse with horizontal major axis of the standard form:
(x-h)^2/a^2+(y-k)^2/b^2=1, a>b, (h,k) being the (x,y) coordinates of the center.
For given equation:
center:(0,0)
a^2=25
a=5
length of horizontal major axis=20=10
domain: [-5,5] (length of major axis including end points)
..
b^2=16
b=4
length of minor axis=2b=8
range [-4,4] (length of minor axis including end points)
..
see graph below:
y=±(16-16x^2/25)^.5
(