SOLUTION: What is the x-intecept with the vertex(4,75) and y-intercept(0,27)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: What is the x-intecept with the vertex(4,75) and y-intercept(0,27)      Log On


   



Question 528173: What is the x-intecept with the vertex(4,75) and y-intercept(0,27)
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
What is the x-intecept with the vertex(4,75) and y-intercept(0,27)
**
Standard form of equation for a parabola: y=A(x-h)^2+k, (h,k) being the (x,y) coordinates of the vertex, A=multiplier which affects the steepness or slope of the curve.
For given problem:
y=A(x-4)^2+75
Solve for A using given point (0,27)
27=A(0-4)^2+75
27=16A+75
16A=27-75=-48
A=-3
Equation of given parabola:
y=-3(x-4)^2+75
solving for x-intercepts
set y=0
-3(x-4)^2+75=0
(x-4)^2=-75/-3=25
take sqrt of both sides
x-4=±√25=±5
x=4±5
x=9
or
x=-1
se graph below as a visual check on answers:
+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+100%2C-3%28x-4%29%5E2%2B75%29+