Question 527256: Find the focus of the parabola that has vertex (7, 1), opens horizontally, and passes through the point (11, 0).
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find the focus of the parabola that has vertex (7, 1), opens horizontally, and passes through the point (11, 0)
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Standard form of equation for given parabola:
(y-k)^2=4p(x-h), with (h,k) being the (x,y) coordinates of the vertex
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For given equation:
(y-1)^2=4p(x-7)
using given point (11,0) to find 4p
4p=(0-1)/(11-7)=-1/4
p=-1/16
Equation: (y-1)^2=(-1/4)(x-7)
This is an equation of a parabola which opens leftwards, axis of symmetry, y=1
Ans: focus: (111/16,1) (p units from x-coordinate of vertex(7,1) on axis of symmetry)
note: 7=112/16
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