SOLUTION: f(x)=1/2(x+6)^2+6 Find vertex, line of symmetry max/min and graph.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: f(x)=1/2(x+6)^2+6 Find vertex, line of symmetry max/min and graph.      Log On


   

Question 512806: f(x)=1/2(x+6)^2+6
Find vertex, line of symmetry max/min and graph.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=1/2(x+6)^2+6
Find vertex, line of symmetry max/min and graph.
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Given equation is that of a parabola of standard form: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex.
For given equation: f(x)=1/2(x+6)^2+6
Vertex: (-6, 6)
Line of symmetry: x=-6
Parabola opens upwards, so function has a minimum at y=6
see graph below:
+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C%281%2F2%29%28x%2B6%29%5E2%2B6%29+