SOLUTION: Find the center and the radius of x^2+y^2+2 x+6 y+1=0
Algebra
->
Quadratic-relations-and-conic-sections
-> SOLUTION: Find the center and the radius of x^2+y^2+2 x+6 y+1=0
Log On
Algebra: Conic sections - ellipse, parabola, hyperbola
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Quadratic-relations-and-conic-sections
Question 503161
:
Find the center and the radius of x^2+y^2+2 x+6 y+1=0
Answer by
lwsshak3(11628)
(
Show Source
):
You can
put this solution on YOUR website!
Find the center and the radius
x^2+y^2+2 x+6 y+1=0
complete the square
(x^2+2x+1)+(y^2+6y+9)=-1+1+9
(x+1)^2+(y+3)^2=9
Center: (-1, -3)
Radius=√9=3