SOLUTION: what is the shape of the graph of the equation below? x^2/3+(y-4)^2/6^2=1

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: what is the shape of the graph of the equation below? x^2/3+(y-4)^2/6^2=1      Log On


   



Question 498944: what is the shape of the graph of the equation below?
x^2/3+(y-4)^2/6^2=1

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
to graph this equation you have to solve for y.
after solving for y, we get:
y = 4 +/- sqrt(36 - 12x^2)
the graph of that equation looks like this:

it looks very much like a vertical ellipse.
here's a reference on ellipses.
http://www.purplemath.com/modules/sqrellps.htm
here's a lesson that i wrote on ellipses.
http://www.algebra.com/algebra/homework/equations/THEO-20100329.lesson
read as much as you need if you need to read.