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Question 491832: find the ratius and center of the circle:
x^2+y^2-8x+14y+29=0
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! find the ratius and center of the circle:
x^2+y^2-8x+14y+29=0
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Standard form of equation for circle: (x-h)^2+(y-k)^2=r^2, (h,k) being coordinates of center and r=radius.
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x^2+y^2-8x+14y+29=0
completing the square:
(x^2-8x+16)+(y^2+14y+49)=-29+16+49=36
(x-4)^2+(y+7)^2=36
Center: (4, -7)
Radius=√36=6
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