SOLUTION: What is the focus of the parabola with equation 16y = x^2? show work please :)

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Question 475245: What is the focus of the parabola with equation 16y = x^2? show work please :)
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
4cy+=+x%5E2 ==> 4c = 16 ==> c = 4 (parabola opens upward with vertex at (0,0)). ==> Focus is (0, 4).