SOLUTION: (a) Graph x^2/16 - y^2/25 = 1. Show how you arrived at the graph by determining the (b) x-intercepts, (c) extent of the graph and the (d)asymptotes. Please explain fully. I r

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: (a) Graph x^2/16 - y^2/25 = 1. Show how you arrived at the graph by determining the (b) x-intercepts, (c) extent of the graph and the (d)asymptotes. Please explain fully. I r      Log On


   

Question 470992: (a) Graph x^2/16 - y^2/25 = 1.
Show how you arrived at the graph by determining the (b) x-intercepts, (c) extent of the graph and the (d)asymptotes.
Please explain fully. I really don't understand this question. Thanks.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Standard Form of an Equation of an Hyperbola opening right or left is  %28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 

where Pt(h,k) is a center  with vertices 'a' units right and left of center.

Asymptotes passing thru the center with slope = ± b/a 

foci being ± sqrt(a^2 + b^2)from center  along axis of symmetry y = k



 x^2/16 - y^2/25 = 1 C(0,0) Vertices: (4,0) and (-4,0)

Foci = (-6.4,0) and (6.4,0)  ± sqrt(41)= ± 6.4

Asymptotes  y = 5/4 and y = -5/4