SOLUTION: Identify the vertices and foci. (x+3)^2/16+(y-1)^2/25=1

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Question 467420: Identify the vertices and foci.
(x+3)^2/16+(y-1)^2/25=1
Answer by lwsshak3(11628) About Me  (Show Source):
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Identify the vertices and foci.
(x+3)^2/16+(y-1)^2/25=1
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(x+3)^2/16+(y-1)^2/25=1
This is an ellipse with a vertical major axis.
Center:(-3,1)
a^2=25
a=5
length of major axis=2a=10
vertices at (-3,1±5) or (-3,6) and (-3,-4)
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b^2=16
b=4
length of minor axis=2b=8
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c^2=a^2-b^2=25-16=9
c=√9=3
foci:(-3±3) or (-3,0) and (-3,-6)
See graph below as a visual check on answers
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y=(25-25(x+3)^2/16)^.5+1