SOLUTION: x^2 - 4x + y^2 - 4y + 4 = 12

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Question 464886: x^2 - 4x + y^2 - 4y + 4 = 12
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 

where Pt(h,k) is the center and r is the radius



x^2 - 4x  + y^2 - 4y + 4 = 12  |Completing square to put into standard form

(x-2)^2 - 4 +(y-2)^2 - 4 + 4 = 12

(x-2)^2 + (y-2)^2 = 16

Circle with C(2,2) and radius of 4