SOLUTION: what is the center of 4x^2+4y^2+32y=0
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Question 463063
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what is the center of 4x^2+4y^2+32y=0
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what is the center of 4x^2+4y^2+32y=0
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4x^2+4y^2+32y=0
divide by 4
x^2+y^2+8y=0
complete the square
x^2+(y^2+8+16)-16=0
x^2+(y+4)^2=16
This is a circle with center at (0,-4) and radius of 4