SOLUTION: Use these additional characteristics, to write the equation of the hyperbola: it has asymptotes y=2/3x and y=-2/3x a horizontal transverse axis, and one vertex is located at (

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Use these additional characteristics, to write the equation of the hyperbola: it has asymptotes y=2/3x and y=-2/3x a horizontal transverse axis, and one vertex is located at (      Log On


   

Question 46294: Use these additional characteristics, to write the equation of the hyperbola:
it has asymptotes y=2/3x and y=-2/3x
a horizontal transverse axis, and
one vertex is located at (-3,0).
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
Horizontal transverse axis means that the hyperbola is horizontal.
The slope for the asymptotes would be: b/a
b = 2
a = 3
The center is (0,0) because the asymptote's y-intercept is zero.
Vertices: (-3,0) and (3,0)
%28%28x+-+h%29%5E2%29%2Fa%5E2+-+%28%28y+-+k%29%5E2%29%2Fb%5E2+=+1
%28x%5E2%29%2F9+-+%28y%5E2%29%2F4+=+1