SOLUTION: Please explain why the graph of (x-h)^2 = 4p(y-k) has a y-intercept of (0, h^2/4p +K). Thanks.
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Question 46224
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Please explain why the graph of (x-h)^2 = 4p(y-k) has a y-intercept of
(0, h^2/4p +K). Thanks.
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Nate(3500)
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(x-h)^2 = 4p(y-k)
(0-h)^2 = 4p(y-k)
h^2 = 4p(y-k)
h^2/4p = y-k
h^2/4p+k = y