SOLUTION: {{{x^2}}}+{{{y^2}}}=36 {{{(x^2)/(16)}}}+{{{(y^2)/(64)}}}=1 What are the points of intersection?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: {{{x^2}}}+{{{y^2}}}=36 {{{(x^2)/(16)}}}+{{{(y^2)/(64)}}}=1 What are the points of intersection?      Log On


   

Question 459518: x%5E2+y%5E2=36
%28x%5E2%29%2F%2816%29+%28y%5E2%29%2F%2864%29=1
What are the points of intersection?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+y^2=36
x^2/16+y^2/64=1
..
x^2+y^2=36
4x^2+y^2=64
-3x^2=-28
x^2=28/3
x=±√(28/3)=±3.055
..
y^2=36-x^2=26.67
y^2=√(26.67)=±5.164
..
Ans:
Points of intersection:(-3.055,-5.164),(3.055,-5.164),(3.055,5.164),(-3.055,5.164)
See the graph below as a visual check on the answers
..
y=(36-x^2)^.5
y=(64-4x^2)^.5