SOLUTION: find the foci of the hyperbola having the equation 4y^2-x^2=16

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Question 450257: find the foci of the hyperbola having the equation 4y^2-x^2=16
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
The center of the hyperbola is the point (0,0). The transverse axis is the y-axis.
Now for the hyperbola, b%5E2+=+c%5E2+-+a%5E2, or 16+=+c%5E2+-+4, or
c%5E2+=+20, or c+=+2sqrt%285%29.
The foci are (0,2sqrt%285%29) and (0,-2sqrt%285%29).