SOLUTION: find the equation for a hyperbola with vertives at (-3,0) (3,0) and foci at (-11,0) (11,0)

 

Hi, 

Standard Form of an Equation of an Hyperbola opening right and left is:  

 

where Pt(h,k) is a center  with vertices 'a' units right and left of center.

vertices at (-3,0) (3,0) and foci at (-11,0) (11,0)

  C(0,0) with vertices at (-3,0) (3,0)

foci at (-11,0) (11,0), that is: sqrt(9+b^2) = 11   b^2 = 112