SOLUTION: graph. label vertices, foci, and centers where applicable. 1. (x+2)^2 + (y-3)^2 = 16 2. (x-8)^2 + (y-5)^2 =1

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: graph. label vertices, foci, and centers where applicable. 1. (x+2)^2 + (y-3)^2 = 16 2. (x-8)^2 + (y-5)^2 =1       Log On


   

Question 448898: graph. label vertices, foci, and centers where applicable.
1. (x+2)^2 + (y-3)^2 = 16
2. (x-8)^2 + (y-5)^2 =1
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 

where Pt(h,k) is the center and r is the radius

1. (x+2)^2 + (y-3)^2 = 16  C(-2,3) r = 4

2. (x-8)^2 + (y-5)^2 =1    C(8,5)  r = 0