Question 448864: Find the equation for the hyperbola?
vertices at (-1,0),(1,0) and asymptote of the line y=3x
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi
Find the equation for the hyperbola with:
vertices at (-1,0),(1,0)(opens right and left) and asymptote of the line y=3x
x^2/1^2 - y^2/b^2 = 1 Center(0,0) and a = 1
y = 3x that is b/a = 3 b = 3
Standard Form of an Equation of a Circle is 
where Pt(h,k) is the center and r is the radius
Standard Form of an Equation of an Ellipse is 
where Pt(h,k) is the center and a and b are the respective vertices distances from center.
Standard Form of an Equation of an Hyperbola is  where Pt(h,k) is a center with vertices 'a' units right and left of center.
Standard Form of an Equation of an Hyperbola opening up and down is:
 where Pt(h,k) is a center with vertices 'b' units up and down from center.
Using the vertex form of a parabola opening up or down, 
where(h,k) is the vertex
The standard form is  , where the focus is (h,k + p)
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