SOLUTION: write an equation for a graph that is the set of all points in the plane that are equidistant from the given point and the given line. F(0,2) y= -2

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: write an equation for a graph that is the set of all points in the plane that are equidistant from the given point and the given line. F(0,2) y= -2      Log On


   



Question 448829: write an equation for a graph that is the set of all points in the plane that are equidistant from the given point and the given line.
F(0,2) y= -2

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi
write an equation for a graph that is the set of all points in the plane that
are equidistant from the given point(0,2) and y = -2
Parabola opening upward: C(0,0)
4py = x^2 p = 2
8y = x^2 or y = x^2/8

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2
where Pt(h,k) is the center and r is the radius
Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+
where Pt(h,k) is the center and a and b are the respective vertices distances from center.
Standard Form of an Equation of an Hyperbola is %28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 where Pt(h,k) is a center with vertices 'a' units right and left of center.
Standard Form of an Equation of an Hyperbola opening up and down is:
%28y-k%29%5E2%2Fb%5E2+-+%28x-h%29%5E2%2Fa%5E2+=+1 where Pt(h,k) is a center with vertices 'b' units up and down from center.
Using the vertex form of a parabola opening up or down, y=a%28x-h%29%5E2+%2Bk
where(h,k) is the vertex
The standard form is %28x+-h%29%5E2+=+4p%28y+-k%29, where the focus is (h,k + p)