SOLUTION: How do you find the parabola equation for a parabola that's maximum is (2,8) and the start of the parabola is (o,6) ?

 

Hi

Using the vertex form of a parabola,  where(h,k) is the vertex

maximum is (2,8) and the start of the parabola is (0,6) ?

Standard form is , where  the focus is (h,k + p) 

  y = a(x-2)^2 +8  |Using point (0,6) to solve for a

  6 = a*4 + 8

 -2 = 4a

  -1/2 = a

y = -.5(x-2)^2 +8   OR -2(y-8) = (x-2)^2