SOLUTION: x^2-18x-y^2+12y=19, find the center and vertices

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Question 445932: x^2-18x-y^2+12y=19, find the center and vertices
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi, Note: 

Standard Form of an Equation of an Hyperbola opening right and left is  

            %28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 

where Pt(h,k) is a center  with vertices 'a' units right and left of center.

 x^2-18x-y^2+12y=19

(x-9)^2 -81 -[(y-6)^2-36] = 19

(x-9)^2 -81 -(y-6)^2+36 = 19

(x-9)^2 -(y-6)^2 = 64

%28x-9%29%5E2%2F64+-%28y-6%29%5E2%2F64=1  C(9,6) with vertices V(1,6) and V(17,6)