SOLUTION: y=2x^2+x-6 Find the Vertex, Min or Max, Zero's, Y-intercept, Axis of Symmetry, Wider or Thinner, Domain, Range?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: y=2x^2+x-6 Find the Vertex, Min or Max, Zero's, Y-intercept, Axis of Symmetry, Wider or Thinner, Domain, Range?      Log On


   

Question 439648: y=2x^2+x-6 Find the Vertex, Min or Max, Zero's, Y-intercept, Axis of Symmetry, Wider or Thinner, Domain, Range?
Answer by Gogonati(855) About Me  (Show Source):
You can put this solution on YOUR website!
The domain and range of the function y=2x%5E2%2Bx-6 is the set of real numbers.
Since this function represent a parabola we rewrite it in standard form:
y=2%28x%5E2%2B%281%2F2%29x%2B1%2F16%29-1%2F8-6, simplify y=2%28x%2B1%2F4%29%5E2-49%2F8.
The vertex is: (-1/4, -49/8). The minimum value is -49/8 and the axis of symmetry
is: x=-1/4. The x-intercepts are: (-2, 0)and (2/3, 0)
graph%28600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+2x%5E2%2Bx-6%29