SOLUTION: what is the vertex of y=5x^2+2x-4

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Question 438164: what is the vertex of y=5x^2+2x-4
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
what is the vertex of y=5x^2+2x-4
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Since 5 is positive, the parabola opens up.
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minimum occurs when x = -b/(2a) = -2/(10) = -1/5
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f(-1/5) = -4.2
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Vertex: (-0.2, -4.2)
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graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C5x%5E2%2B2x-4%29
Cheers,
Stan H.