SOLUTION: For the following ellipse, find the length of the major axis, the length of the minor axis and the 2 vertices. (x-3)^2/121 + (y+2)^2/31=1 THANK YOU SO MUCH! I've been trying

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: For the following ellipse, find the length of the major axis, the length of the minor axis and the 2 vertices. (x-3)^2/121 + (y+2)^2/31=1 THANK YOU SO MUCH! I've been trying       Log On


   

Question 422410: For the following ellipse, find the length of the major axis, the length of the minor axis and the 2 vertices.
(x-3)^2/121 + (y+2)^2/31=1
THANK YOU SO MUCH! I've been trying to do this for like an hour now
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

 Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+

where Pt(h,k) is the center 

and a and b  are the respective vertices, "distance from center"

%28x-3%29%5E2%2F121+%2B+%28y%2B2%29%5E2%2F31=1  center is Pt(3,-2)

 a = 11  and b = sqrt(31)= 5.568

major axis has a length of 22, minor 2*5.568= 11.136

Vertices (14,2)(-8,2) and (3,3.568) (3,-7.568)

always recommend sketching it out: