SOLUTION: Find the center of this hyperbola: -4x^2+9y^2+16x-18y+29=0

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Question 422333: Find the center of this hyperbola: -4x^2+9y^2+16x-18y+29=0
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Finding the center of this hyperbola: 

 -4x^2+9y^2+16x-18y+29=0

 9(y^2-2y)  - 4(x^2-4x) + 29 = 0  |Completing the square

9[(y-1)^2-1  - 4[(x-2)^2 -4] + 29 = 0

9(y-1)^2 -9 - 4(x-2)^2 +16 + 29 = 0

9(y-1)^2 - 4(x-2)^2 +36 = 0

 4(x-2)^2 - 9(y-1)^2 = 36

 %28x-2%29%5E2%2F9+-+%28y-1%29%5E2%2F4+=+1  Center Pt(2,1)