SOLUTION: The graph of the equation below is a circle. What is the length of the radius of the circle? (x+5)^2+(y+7)^2=21^2

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: The graph of the equation below is a circle. What is the length of the radius of the circle? (x+5)^2+(y+7)^2=21^2      Log On


   

Question 408938: The graph of the equation below is a circle. What is the length of the radius of the circle?
(x+5)^2+(y+7)^2=21^2
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

%28x%2B5%29%5E2%2B%28y%2B7%29%5E2=21%5E2
A circle is the set of all points that are the same distance, r, from a fixed point.
General Formula: X%5E2+%2B+Y%5E2=r%5E2 where r is the radius

so, in your case r=21