SOLUTION: One Minor axis vertex is located at (2,-2).Find the other minor axis vertex for the ellipse defined by the equation. (x-1)^2/1 + (y+2)^2/49 =1. I know that the center is (1,-2) and

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: One Minor axis vertex is located at (2,-2).Find the other minor axis vertex for the ellipse defined by the equation. (x-1)^2/1 + (y+2)^2/49 =1. I know that the center is (1,-2) and      Log On


   

Question 390535: One Minor axis vertex is located at (2,-2).Find the other minor axis vertex for the ellipse defined by the equation. (x-1)^2/1 + (y+2)^2/49 =1. I know that the center is (1,-2) and A^2= 49 A=7 but I don't know what to do after that to solve this problem. please help.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,  

Ellipse: (x-1)^2/1 + (y+2)^2/49 =1 with one minor axis vertex at (2,-2)

Yes! Center is Pt(1-2).  Considering the symmety of an Ellipse...

That would determine that (0,-2) would be the other minor axis vertex