SOLUTION: one x-intercept for a parabola is at the point (0.6,0)use the quadratic formula to find the other x-intercept for the parabola defined by the equation: y=-5x^2+8x-3.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: one x-intercept for a parabola is at the point (0.6,0)use the quadratic formula to find the other x-intercept for the parabola defined by the equation: y=-5x^2+8x-3.       Log On


   

Question 389241: one x-intercept for a parabola is at the point (0.6,0)use the quadratic formula to find the other x-intercept for the parabola defined by the equation: y=-5x^2+8x-3.
Found 2 solutions by richard1234, ewatrrr:
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
If we use the quadratic formula,

x+=+%28-8+%2B-+sqrt%2864+-+4%2815%29%29%29%2F-10+=+%28-8+%2B-+2%29%2F-10 = 0.6 or 1, so 1 is the other x-intercept.

There's a simpler solution that doesn't involve the quadratic formula. If you know that the sum of the roots of the polynomial is -b/a = -8/-5 = 1.6, we have 1.6 = 0.6 + x, x = 1.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

y= -5x^2+8x-3

at x-intercept , y = 0

 -5x^2 + 8x - 3 = 0

uaing the Quadratic Formula to solve

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

x+=+%28-8+%2B-+sqrt%28+4%29%29%2F%28-10%29+

x+=+%28-8+%2B-+2%29%2F%28-10%29+

   x = 6/10 = .6 (already determined by the question)

   x = 10/10 = 1