|
Question 38909: What is ysquared-4y-4x=0 put in standard form and graphed
Answer by fractalier(6550)   (Show Source):
You can put this solution on YOUR website! From
y^2 - 4y - 4x = 0
we complete the square, also add 4x to both sides
y^2 - 4y + 4 = 4x + 4
(y - 2)^2 = 4(x + 1)
now divide by four and subtract one and get
(1/4)(y - 2)^2 = x + 1
x = (1/4)(y - 2)^2 - 1
This is a wider-than-normal parabola, concave right, with vertex at (-1, 2).
|
|
|
| |
