Question 388449: Graph the parabola
y=(x+1)^2-1
I found the vertex to be (-1,-1)
axis is -1 and a=1
But I don't remember how to find the points. Found 2 solutions by Fombitz, stanbon:Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! Which points?
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Intercepts?
Set solve for .
Set solve for .
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Points on the curve?
Choose points equidistant from x=-1, solve for y.
Example, if ,
You can put this solution on YOUR website! Graph the parabola
y=(x+1)^2-1
I found the vertex to be (-1,-1)
axis is -1 and a=1
But I don't remember how to find the points.
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You need three points to determine a parabola.
You have the vertex at (-1,-1)
The y-intercept ?
Let x = 0, then y = (0+1)^2-1 = 0
That gives you point (0,0)
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The x-intercept ?
Let y = 0 and solve for "x" to get
(0,0) and (-2,0)
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Cheers,
Stan H.
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