SOLUTION: Please....Find the vertex,focus, and directix of the graph of the equation 8(y+2)=(x+6)^2

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Please....Find the vertex,focus, and directix of the graph of the equation 8(y+2)=(x+6)^2      Log On


   

Question 38778: Please....Find the vertex,focus, and directix of the graph of the equation
8(y+2)=(x+6)^2
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
8%28y%2B2%29=%28x%2B6%29%5E2
y=%281%2F8%29%28x%2B6%29%5E2-2
p=%281%2F4a%29=%281%2F%281%2F2%29%29=%282%29
Vertex: (-6,-2)
Focus: (-6,0)
Directix: y=-4