SOLUTION: can you please help me write the equation in standard form for the parabola with vertex (0,0) and the directrix y=-11

Hi,         

Note: for a parabola, 4p(y-k) = (x-h)^2 where (h,k) is the vertex and 

p the distance from the focus to the vertex. in this ex vertex is Pt(0,0)



Directrix y = -11 tells us p = 11 as the directrix is the same distance

from the vertex as is the focus.

 4p(y-k) = (x-h)^2

  4*11y = x^2

      y = x^2/44  the standard form for this parabola