SOLUTION: What is the focus of the given parabola x^2+4y-4=0

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Question 385902: What is the focus of the given parabola x^2+4y-4=0
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
+x%5E2%2B4y-4=0 is the same as x%5E2+=+-4%28y-1%29. The standard form of the equation of the parabola of this type is %28x+-+h%29%5E2+=+4p%28y-k%29, where p is the directed distance of the vertex from the focus. Here p = -1. Since the vertex is (0,1), the focus is (0,0).