SOLUTION: Find the vertices, foci, and minor axis. x^2/36 + y^2/16 = 1

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Question 384492: Find the vertices, foci, and minor axis.
x^2/36 + y^2/16 = 1
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Note: Standard Equation for an ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1

where Pt(h,k) is the center and vertices are determined by distance of a and b from center.

x%5E2%2F36+%2B+y%5E2%2F16+=+1 In this case:  Pt(0,0) is the Center.

Vertices (-6,0) and (6,0). (0,-4) and (0,4)

Foci: c^2 = 36-16 = 20  c = 2sqrt(5)=4.47 Foci are (4.47,0) and (4.47,0)

Minor axis is x = 0