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Question 381342: Question reads:
"Complete the square on the hyperbola: x^2-4y^2+2x+8y-19=0. Finally, draw a quick sketch. A sketch from a graphics calculator is acceptable."
Don't know to complete the square or what to punch in on "y=" on my graphing calculator! Thanks a bunch!
Zach
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! "Complete the square on the hyperbola: x^2-4y^2+2x+8y-19=0. Finally, draw a quick sketch. A sketch from a graphics calculator is acceptable."
Don't know to complete the square or what to punch in on "y=" on my graphing calculator!
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x^2-4y^2+2x+8y-19=0
Complete the square:
x^2+2x+1 -4(y^2-2y+1) = 19 + 1 -4
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(x+1)^2 -4(y-1)^2 = 16
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Divide by 16 to get:
(x+1)^2/16 - (y-1)^2/4 = 1
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The graph is a hyperbola opening to the right and left
with center at (-1,1)
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Yes, it's a challenge to put that in a graphing calculator.
Check with your friends and/or you teacher.
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Cheers,
Stan H.
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