SOLUTION: What is the identity of this conic? 4x^2+4y^2-3x+2y+2=0
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Question 376354
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What is the identity of this conic?
4x^2+4y^2-3x+2y+2=0
Answer by
solver91311(24713)
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There are both x-squared and y-squared terms, so it is NOT a parabola.
The signs on the x-squared and y-squared terms are the same, so it is NOT a hyperbola.
The coefficients on the x-squared and y-squared terms are NOT different, so it is NOT an ellipse.
Therefore, it must be a circle.
John
My calculator said it, I believe it, that settles it