SOLUTION: How do you graph this conic section equation? (x-0)² = (y-2)

(x-0)² = (y-2) 

Put a 1 coefficient on the right:

(x-0)² = 1(y-2)

Now it is in the form

(x-h)² = 4p(y-k)

which has its vertex at the point (h,k) = (0,2), 

4p = 1, so p = 

it has its focus at (h,k+p) = (0,2+) = F(0,)

its directrix is the horizontal line whose equation is 

y = k-p, or y = 2- or y =  in green:


   

Edwin