Question 353217: identify the vertex the axis of symmetry the max or min value and the range of each parabola
y=x^2+2x+1 Answer by ewatrrr(24785) (Show Source):
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y=x^2+2x+1
this is in a general form of an equation for a parabola: y = ax^2 + bx + c
and the axis of symmetry is x = -b/(2a)
x = -1 is the axis of symmerty.
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*Note: Vertex form of the equations would be:
y = (x + 1)(x + 1) = (x+1)^2
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general vertex form of an equation for a parbaola is y = a(x - h)^2 +k
where (x.k) is the vertex
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this parabola opens upward with a min value of 0, it's vertex is (-1, 0)
and range is [0, infinity)
