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Question 350842: Please identify the type of conic section whose equation is given and find the vertices and foci.
y^2 - 8y = 6x - 16
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Please identify the type of conic section whose equation is given and find the vertices and foci.
y^2 - 8y = 6x - 16
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y^2-8y+? = 6x-16 + ?
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Complete the square on the y-terms.
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y^2-8y+4^2 = 6x-16+4^2
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Factor:
(y-4)^2 = 6(x-0)
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4p = 6
p = 3/2
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Type: parabola opening to the right
Vertex: (4,0)
Focus: (4+3/2,0) or (5.5,0
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Cheers,
Stan H.
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