SOLUTION: Find the eccentricity of the hyperbola given by x^2/5^2-y^2/2^2=1

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Question 342914: Find the eccentricity of the hyperbola given by x^2/5^2-y^2/2^2=1
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2F5%5E2-y%5E2%2F2%5E2=1
For this equation, a%5E2+=+5%5E2 and b%5E2+=+2%5E2. That makes a = 5 and b = 2. Also, in a hyperbola, c%5E2+=+a%5E2+%2B+b%5E2 so c%5E2+=+5%5E2+%2B+2%5E2+=+25%2B4+=+29. That makes c+=+sqrt%2829%29.

Eccentricity is c/a do for this hyperbola the eccentricity is sqrt%2829%29%2F5